Best answer: How many moles are there in 10 grams of sodium hydroxide?

How many moles are there in 10g NaOH?

Answer: The answer is 39.99711. We assume you are converting between grams NaOH and mole.

How many moles are in 20 grams of NaOH?

20 gr of NaOH correspond to 0.5 moles which are contained in 0.5 liter of solution.

How many moles are in NaOH?

First, the molar mass of NaOH is 39.997 g/mol. Divide the mass by the molar mass and you’ll have the equation: 60 g / 39.997 g/mol. The grams cancel and you are left with 1.50 moles of NaOH.

How many grams are in 1 mole of sodium hydroxide?

The molar mass tells you the mass of exactly one mole of a given substance. In this case, sodium hydroxide has a molar mass of 39.997 g mol−1 , which implies that one mole of sodium hydroxide has a mass of 39.997 g .

How many grams is 10 moles of water?

So, 10 mole of water will weigh (18×10) = 180g.

How many moles are in 4.75 g of sodium hydroxide?

4.75 g of NaOH (1.19 x 101 mol NaOH) Answer: The molar mass of NaOH was solve in section A to be 40 g/mol.

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How many moles are in 4 grams of NaOH?

=0.10 (approx.)

How do I calculate moles?

How to find moles?

  1. Measure the weight of your substance.
  2. Use a periodic table to find its atomic or molecular mass.
  3. Divide the weight by the atomic or molecular mass.
  4. Check your results with Omni Calculator.

How do you find the moles of NaOH?

Step 1: Calculate the amount of sodium hydroxide in moles

  1. Amount of solute in mol = concentration in mol/dm 3 × volume in dm 3
  2. Amount of sodium hydroxide = 0.100 × 0.0250.
  3. = 0.00250 mol.
  4. The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H 2O(l)
  5. So the mole ratio NaOH:HCl is 1:1.

How many moles are there in 40g of NaOH?

1 mole of NaOH =40g by mass /40g by molar mass. Which is =1. 1 mole of NaOH contains 7.53*10^23 atoms.

How many grams are in 3 moles of NaOH?

A 3.0 M solution of NaOH has 3.0 moles of NaOH per liter of solution. There are 0.25 L of solution (250mL⋅1L1000mL) , so there are 0.25L⋅3.0mol/L=0.75mol of NaOH. The molar mass of NaOH is 40.0 g/mol, so there are 0.75mol⋅40.0g/mol=30g of NaOH, 30.