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## How many moles are there in 10g NaOH?

Answer: The answer is 39.99711. We assume you are converting between grams NaOH and mole.

## How many moles are in 20 grams of NaOH?

20 gr of NaOH correspond to 0.5 moles which are contained in 0.5 liter of solution.

## How many moles are in NaOH?

First, the molar mass of NaOH is 39.997 g/mol. Divide the mass by the molar mass and you’ll have the equation: 60 g / 39.997 g/mol. The grams cancel and you are left with 1.50 moles of NaOH.

## How many grams are in 1 mole of sodium hydroxide?

The molar mass tells you the mass of exactly one mole of a given substance. In this case, sodium hydroxide has a molar mass of 39.997 g mol−1 , which implies that one mole of sodium hydroxide has a mass of 39.997 g .

## How many grams is 10 moles of water?

So, 10 mole of water will weigh (18×10) = 180g.

## How many moles are in 4.75 g of sodium hydroxide?

4.75 g of NaOH (1.19 x 101 mol NaOH) Answer: The molar mass of NaOH was solve in section A to be 40 g/mol.

## How many moles are in 4 grams of NaOH?

=0.10 (approx.)

## How do I calculate moles?

How to find moles?

- Measure the weight of your substance.
- Use a periodic table to find its atomic or molecular mass.
- Divide the weight by the atomic or molecular mass.
- Check your results with Omni Calculator.

## How do you find the moles of NaOH?

Step 1: Calculate the amount of sodium hydroxide in moles

- Amount of solute in mol = concentration in mol/dm
^{3}× volume in dm^{3} - Amount of sodium hydroxide = 0.100 × 0.0250.
- = 0.00250 mol.
- The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H
_{2}O(l) - So the mole ratio NaOH:HCl is 1:1.

## How many moles are there in 40g of NaOH?

1 mole of NaOH =40g by mass /40g by molar mass. Which is =1. 1 mole of NaOH contains 7.53*10^23 atoms.

## How many grams are in 3 moles of NaOH?

A 3.0 M solution of NaOH has 3.0 moles of NaOH per liter of solution. There are 0.25 L of solution (250mL⋅1L1000mL) , so there are 0.25L⋅3.0mol/L=0.75mol of NaOH. The molar mass of NaOH is 40.0 g/mol, so there are 0.75mol⋅40.0g/mol=30g of NaOH, 30.